Hi everyone,
I need you to find the mistakes of this solution given by a student. You just need to describe
i) where is the mistake
ii) what is the correct solution.
Lastly,
iii) what is the difficulty that you find in this chapter?
Remember to sign off your name.
31 comments:
How To Answer????
If anyone finds out please let me know ASAP.... email me but dont msn my mobile....or sms me PLEASE & THANK YOU
-[(x-7/2) =-93/4
i am not sure...
dunno lu.
i) behind never minus (7/2)^2
ii) -maximun turning point
- x-intercept = 0.184 or -5.158
- y-intercept = 6.816
- mid-point = -2.487
iii) Very easy to make calculations mistake during the steps.
answer wrong, i dont know. cause most likely is wrong. :D
dun understand lu.. ahhaha
dunno where is the mistake ...
dunno know therefore i dunno wad's the correct solution ...
i feel that the difficulty in this topic is that i dun know how to do completing square !
~aLiCiA
i duno the mistake how i noe the correct solution.haha.the difficult thing is the completing the square. very lecey.
-nadiiiiahhhh
i)-1 times -93/4=93/4
ii)max tp(7/2,93/4)
when x=0,y=-[(0-7/2)^2-93/4]
so -(49/4)+93/4
=-11
when y=0,(x-7/2)^2+93/4=0
(x-7/2)^2=-93/4
because there has no root of -93/4
so it cannot solve it
iii)NA
1)*the second step of y-intercept:
-[49/4-93/4]≠49/4－93/4
*the second step of x-intercept:
-(x-7/2)^2+93/4=0≠－（x-7/2)^2=93/4
2)max t.p. =〉（7/2，93/4）
y-intrcept => x=0,
∴y=-[(0-7/2)^2-93/4]
=-[49/4-93/4]
=11
x-intercept => y=0,
∴-[(x-7/2)^2-93/4]=0
（x-7/2)^2=93/4
(x-7/2)=√93/4
x-7/2=4.82 or x-7/2=-4.82
x=8.32 0r x=-1.32
3)nil
1)*the second step of y-intercept:
-[49/4-93/4]≠49/4－93/4
*the second step of x-intercept:
-(x-7/2)^2+93/4=0≠－（x-7/2)^2=93/4
2)max t.p. =〉（7/2，93/4）
y-intrcept => x=0,
∴y=-[(0-7/2)^2-93/4]
=-[49/4-93/4]
=11
x-intercept => y=0,
∴-[(x-7/2)^2-93/4]=0
（x-7/2)^2=93/4
(x-7/2)=√93/4
x-7/2=4.82 or x-7/2=-4.82
x=8.32 0r x=-1.32
1)*the second step of y-intercept:
-[49/4-93/4]≠49/4－93/4
*the second step of x-intercept:
-(x-7/2)^2+93/4=0≠－（x-7/2)^2=93/4
2)max t.p. =〉（7/2，93/4）
y-intrcept => x=0,
∴y=-[(0-7/2)^2-93/4]
=-[49/4-93/4]
=11
x-intercept => y=0,
∴-[(x-7/2)^2-93/4]=0
（x-7/2)^2=93/4
(x-7/2)=√93/4
x-7/2=4.82 or x-7/2=-4.82
x=8.32 0r x=-1.32
1)*the second step of y-intercept:
-[49/4-93/4]≠49/4－93/4
*the second step of x-intercept:
-(x-7/2)^2+93/4=0≠－（x-7/2)^2=93/4
2)max t.p. =〉（7/2，93/4）
y-intrcept => x=0,
∴y=-[(0-7/2)^2-93/4]
=-[49/4-93/4]
=11
x-intercept => y=0,
∴-[(x-7/2)^2-93/4]=0
（x-7/2)^2=93/4
(x-7/2)=√93/4
x-7/2=4.82 or x-7/2=-4.82
x=8.32 0r x=-1.32
i)-the second step of y-intercept
-the second step of x-intercept
-the max turning point
ii) y= -[(x-7/2)^2-93/4]
the max t.p => ( 7/2, 93/4)
y-intrcept => x=0
∴ y= -[(0-7/2)^2-93/4]
=-(49/4 - 93/4)
=11
x-intercept => y=0,
∴ -[(x-7/2)^2-93/4]=0
-(x-7/2)^2 + 93//4 =0
-(x-7/2)^2 = -93/4
(x-7/2)^2 = 93/4
x = 7/2+√93/4, 7/2-√93/4
= 8.32 , -1.32
i think is the completing square method
i dunno =)
dunno leh
i dun noe how 2 explain ..
jun yan
~the second line
max point is not (7/2,-93/4)
is (7/2,93/4)
~correction of y-intercept
is y=-[(0-7/2)^2-93/4]
=-[49/4-93/4]
=11
i do not understand the working. Can anyone tell me what is wrong
Yvonne
i dunno how to do completing squares...
i dun't know =))
i dunno =DD
second step of y-intercept second step of x-intercept the max t.p
y= -[(x-7/2)^2-93/4]
the max t.p => ( 7/2, 93/4)
y-intrcept => x=0
∴ y= -[(0-7/2)^2-93/4]
=-(49/4 - 93/4)
=11
x-intercept => y=0,
∴ -[(x-7/2)^2-93/4]=0
-(x-7/2)^2 + 93//4 =0
-(x-7/2)^2 = -93/4
(x-7/2)^2 = 93/4
x = 7/2+√93/4, 7/2-√93/4
= 8.32 , -1.32
the second step of y-intercept
the second step of x-intercept
the max turning point
i dun know to do it...
i dunno....
dunno therefore no answer
difficult to draw graph.....
i)turnin point,y and x intercept are wrong
ii)max t.p (7/2 , 93/4)
y-intercept is suppose to be
-49/4 + 93/4= 11
x-intercept is suppose to be
-(x-7/2)^2= -93/4
(x-7/2)^2= 93/4
x-7/2= +/-root 93/4
x= root 93/4+7/2 &
-root 93/4+7/2
i tink lol
iii)difficulty in completing spuare?? i dunno lol XD
i dunno...
Azleen
max t.p => 7/2, 93/4
y-intercept =-[(0-7/2)^2-(93/4)]=-(49/4-93/4)=-11
Found it diffcult to completing the sq method.
~~Junkai
Sry answer is 11.
Junkai
how to do?
dont even know!
M.X point will be
(7/2 , 93/4 )
Vic
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